1646. Get Maximum in Generated Array

You are given an integer n. An array nums of length n + 1 is generated in the following way:

• nums[0] = 0
• nums[1] = 1
• nums[2 * i] = nums[i] when 2 <= 2 * i <= n
• nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums​​​.

Example 1:

Input: n = 7
Output: 3
Explanation: According to the given rules:
  nums[0] = 0
  nums[1] = 1
  nums[(1 * 2) = 2] = nums[1] = 1
  nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
  nums[(2 * 2) = 4] = nums[2] = 1
  nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
  nums[(3 * 2) = 6] = nums[3] = 2
  nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.

Example 2:

Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0], nums[1], and nums[2] is 1.

Example 3:

Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0], nums[1], nums[2], and nums[3] is 2.

Constraints:

• 0 <= n <= 100

My Approach to given question : -

int getMaximumGenerated(int n) {
        if(n == 0) {
            return 0;
        }
        vector<int> v;
        v.push_back(0);   // v[0] first element
        v.push_back(1);   // v[1] second element
        int MAX = 1;    // since 1 is max of v[0] & v[1]
        for(int i = 2; i <= n; i++) {  // iterate from 2 to n as total n+1 elements are to push   
            if(i%2 == 0) {     // If i is divisible by 2 then val = v[i/2] 
                int val = v[i/2];
                v.push_back(val);
                MAX = max(v[i], MAX);  // update the max value
            }
            else {
                int val = v[i/2]+v[(i/2)+1];   // if i is not divided by 2 then push v[i/2] + v[(i/2)+1]
                v.push_back(val);
                MAX = max(v[i], MAX);  // update max value
            }
        }
        return MAX;
    }